Question

#include<iostream>

using namespace std;
class test
{
int a;
public:
test()
{
    a=0;
}
test operator ++(int)
{        a++;
    return *this;
}
void display()
{
    cout<<a;
}
~test() {
    cout << "DES" << endl;
}
  };
int main()
{
    test t,t1;
    t1 = t++;
    t.display();
    system("pause");
}

The output that i get is :

DES
1Press any key to continue...
DES 
DES

Why does the destructor work before ?

Answer 1

When you are using t++ a temporary object is created. This is the reason you have 3 destructors called for 2 variables. If you use ++t, temporary object would not be created. Which, other than the operator precedence, is the main difference between pre- and post- incrementing.