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#include<iostream>
using namespace std;
int main()
{
int i=2;
cout<<++i<<" "<<++i;
return 0;
}
Why the output of program is ‘4 4’ not ‘3 4’ ?
because both increments occur before the line is output. the actual writing to the screen is delayed until the entire line has been run, but by then the reference for i has already had its value updated.
if you split your cout line into two discrete outputs, things would evaluate as you expect.