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Editorial Team
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Asked: 2026-05-25T05:56:51+00:00

#include<stdio.h> int main() { int a,*b,**c,***d,****e; a=10; b=&a; c=&b; d=&c; e=&d; printf(\na=%d b=%u c=%u

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#include<stdio.h>

int main()
{
    int a,*b,**c,***d,****e;
    a=10;
    b=&a;
    c=&b;
    d=&c;
    e=&d;
    printf("\na=%d b=%u c=%u d=%u e=%u",a,b,c,d,e);
    printf("\n%d %d %d %d %d",a,a+*b,**c+***d+****e);
    return 0;
}

I could not edit this post… All the options to do so are not visible to my browser.I meant to ask why the compiler didnt warn me and is giving me the output as 0 0 for the extra format specifiers.

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1 Answer

  1. Editorial Team

    What do you expect it to print when given five conversion specifications but only three arguments?

    The C standard says, in 7.19.6.1/2

    If there are insufficient arguments for the format, the behavior is undefined.

    In your case, the program happend to print zeroes. In my case, it printed something else.

    EDIT in response to the question “why?”: Most compilers do warn about this error:

    gcc says warning: format ‘%d’ expects a matching ‘int’ argument

    clang says warning: more '%' conversions than data arguments

    icc says warning #267: the format string requires additional arguments

    However, there is no requirement that they must diagnose this. Undefined behavior is just that, undefined. Anything can happen.

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