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Home/ Questions/Q 6866093
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:08:13+00:00 2026-05-27T03:08:13+00:00

index = [0, 2, 5] s = I am like stackoverflow-python for i in

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index = [0, 2, 5]
s = "I am like stackoverflow-python"
for i in index:
        s = s[i].upper()
print(s)

IndexError: string index out of range

I understand that in the first iteration the string, s, become just the first character, an uppercase “I” in this particular case. But, I have tried to do it without the “s = ” , using swapchcase() instead, but it’s not working.

Basically, I’m trying to print the s string with the index letters as uppercase using Python 3.X

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:08:13+00:00Added an answer on May 27, 2026 at 3:08 am

    Strings are immutable in Python, so you need to create a new string object. One way to do it:

    indices = set([0, 7, 12, 25])
    s = "i like stackoverflow and python"
    print("".join(c.upper() if i in indices else c for i, c in enumerate(s)))
    

    printing

    I like StackOverflow and Python
    
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