Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7663359
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T14:02:38+00:00 2026-05-31T14:02:38+00:00

Input file text.txt: foo() { } buz() { } Awk script.awk : BEGIN {

  • 0

Input file text.txt:

foo()
{
}

buz()
{
}

Awk script.awk:

BEGIN {
    RS = "\n\n+";
    FS = "\n";
}
/[a-z]+\(\)\n/ {print "FUNCTION: " $1;}
{print "NOT FOUND: " $0;}

Running script:

awk -f script.awk text.txt

gives:

NOT FOUND: foo()
{
}
NOT FOUND: buz()
{
}

But I’ve expected to match both functions WITH newlines. How to do this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-31T14:02:40+00:00Added an answer on May 31, 2026 at 2:02 pm

    You can try this:

    BEGIN {
        RS = "";
        FS = "\n";
    }
    /[a-z]+\(\)/ {print "FUNCTION: " $1;}
    !/[a-z]+\(\)/ {print "NOT FOUND: " $0;}
    

    If you want to verify that there is nothing after the () you can do this:

    $1~/[a-z]+()$/ {print “FUNCTION: ” $1;}

    I don’t know why newline isn’t matched. Maybe someone would explain it.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have this script #!/bin/bash function labels2 () { awk ' /[0-9]/{ print substr($3,length($3)-11),
I have a text file as input like this:let say it as xyz.txt TIME
Write a program which reads a text file called input.txt which contains an arbitrary
I've got a form uploading input lines of text to a .txt file and
I have a text file (c:\input.txt) which has: 2.0 4.0 8.0 16.0 32.0 64.0
Below is a fairly simple C program to open a text file (input.txt), read
I am parsing an input text file. If I grab the input one line
I wanna stop the reading of my text input file when the word synonyms
I am trying to read in a text input file that contains a list
I would like to read a text file and input its contents into an

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.