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Home/ Questions/Q 8117043
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T04:01:28+00:00 2026-06-06T04:01:28+00:00

Input: List of keys: [ :name :address :work] Map 1: { :name A :address

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Input:

List of keys: [ :name :address :work]
Map 1: { :name "A" :address "A Street" }
Map 2: { :work "Work Ave" }

Output:

([:name "A" nil] [:address "A Street" nil] [:work nil "Work Ave"])

This is what I have at the moment:

(defn maps-iterate [v & ms]
    (map (fn [k] (into [] [k #(map (k %) ms)])) v))

(println (maps-iterate [ :name :address :work ] { :name "A" :address "A Street"} { :work "Work Ave" }))

Which gives me:

([:name #<user$maps_iterate$fn__2$fn__3 user$maps_iterate$fn__2$fn__3@4b14b82b>] 
 [:address #<user$maps_iterate$fn__2$fn__3 user$maps_iterate$fn__2$fn__3@3d47358f>] 
 [:work #<user$maps_iterate$fn__2$fn__3 user$maps_iterate$fn__2$fn__3@e0d5eb7>])
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T04:01:30+00:00Added an answer on June 6, 2026 at 4:01 am

    Try

    (defn maps-iterate [v & ms]
        (map (fn [k] (into [] [k (map #(k %) ms)])) v))
    

    Or even better:

    (defn maps-iterate [v & ms]
        (map (fn [k] (cons k (map k ms))) v))
    

    Note: if all keys are keywords, then you can use them as functions: (map k ms) instead of (map #(k %) ms). If they are not then you can’t use them as functions. You need to write (map #(% k) ms)

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