Question

Input the following little sequential program and its parallelized version in Scala REPL:

/* Activate time measurement in "App" class. Prints [total <X> ms] on exit. */
util.Properties.setProp("scala.time", "true")
/* Define sequential program version. */
object X extends App { for (x <- (1 to 10)) {Thread.sleep(1000);println(x)}}
/* Define parallel program version. Note '.par' selector on Range here. */
object Y extends App { for (y <- (1 to 10).par) {Thread.sleep(1000);println(y)}}

Executing X with X.main(Array.empty) gives:

1
2
3
4
5
6
7
8
9
10
[total 10002ms]

Whereas Y with Y.main(Array.empty) gives:

1
6
2
7
3
8
4
9
10
5
[total 5002ms]

So far so good. But what about the following two variations of the program:

object X extends App {(1 to 10).foreach{Thread.sleep(1000);println(_)}}
object Y extends App {(1 to 10).par.foreach{Thread.sleep(1000);println(_)}}

The give me runtimes of [total 1002ms] and [total 1002ms] respectively. How can this be?

Answer 1

This have nothing to do with parallel collections. The problem is hidden in the function literal. You can see it if you let the compiler show the AST (with option -Xprint:typer):

for (x <- (1 to 10)) {Thread.sleep(1000);println(x)}

produces

scala.this.Predef.intWrapper(1).to(10).foreach[Unit](((x: Int) => {
  java.this.lang.Thread.sleep(1000L);
  scala.this.Predef.println(x)
}))

whereas

(1 to 10).foreach{Thread.sleep(1000);println(_)}

produces

scala.this.Predef.intWrapper(1).to(10).foreach[Unit]({
  java.this.lang.Thread.sleep(1000L);
  ((x$1: Int) => scala.this.Predef.println(x$1))
})

There is a little difference. If you want the expected result you have to change the foreach-expression to

(1 to 10).foreach{x => Thread.sleep(1000);println(x)}

But what is the difference? In your code you declare a block to foreach and after executing the block it will return the function to execute. Then this returned function is delivered to foreach and not the block which contains it.

This mistake is often done. It has to do with the underscore literal. Maybe this question helps you.