Question

InputStream in = ClientSocket.getInputStream();
new Thread()
{
    public void run() {
        while (true)
        {
            int i = in.read();
            handleInput(i);
        }
    }
}.start();

I’m listening to new data on a socket with this code and get:

FaceNetChat.java:37: unreported exception java.io.IOException; must be caught or declared to be thrown
                int i = in.read();
                               ^

When I add “throws IOException” after the “run()” I get:

FaceNetChat.java:34: run() in  cannot implement run() in java.lang.Runnable; overridden method does not throw java.io.IOException
        public void run() throws IOException {
                    ^

It’s probably something simple, but I’m at a loss. How do I get passed this?

Answer 1

You can’t override the interface of Runnable.run() which does not throw an exception. You must instead handle the exception in the run method.

try {
  int i = in.read();
} catch (IOException e) {
  // do something that makes sense for your application
}