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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T05:12:21+00:00 2026-06-05T05:12:21+00:00

Inserting an element into a heap involves appending it to the end of the

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Inserting an element into a heap involves appending it to the end of the array and then propagating it upwards until it’s in the “right spot” and satisfies the heap property, the operation of which is O(logn).

However, in C, for instance, calling realloc in order to resize the array for the new element can (and likely will) result in having to copy the entirety of the array to another location in memory, which is O(n) in the best and worst case, right?

Are heaps in C (or any language, for that matter) usually done with a fixed, pre-allocated size, or is the copy operation inconsequential enough to make a dynamically sized heap a viable choice (e.g, a binary heap to keep a quickly searchable list of items)?

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  1. Editorial Team
    Editorial Team
    2026-06-05T05:12:24+00:00Added an answer on June 5, 2026 at 5:12 am

    A typical scheme is to double the size when you run out of room. This doubling–and the copying that goes with it–does indeed take O(n) time.

    However, notice that you don’t have to perform this doubling very often. If you average out the total cost of all the doubling over all the operations performed on the heap that did not involve doubling, then the cost is indeed inconsequential. (This kind of averaging is known as amortized analysis.)

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