Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8089865
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 5, 20262026-06-05T19:32:41+00:00 2026-06-05T19:32:41+00:00

Instead of prefixing id’s in xml, is it possible to specify the particular layout

  • 0

Instead of prefixing id’s in xml, is it possible to specify the particular layout in code? For example, if I have 3 layouts, each with a button that has an id of “btn”. Is it possible to specify which layout to findViewById(R.id.btn) in?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-05T19:32:43+00:00Added an answer on June 5, 2026 at 7:32 pm

    The basic context is defined via setContentView(R.lyaout.my_layout). If you inflate another layout using LayoutInflater.inflate() you get a layout object, lets call it buttonLayout. You can now differ between this.findViewById(R.id.button) and buttonLayout.findViewById(R.id.button) and both will give you different button references.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I've got some (badly written) legacy code that I have to modify but I'm
Instead of individually calling $(#item).removeClass() for every single class an element might have, is
Instead it just opens the new frame, and when that one closes.. it not
Instead of going through each (+) sign at the left and clicking them to
Instead of www.example.com/author/xyz, I want to use www.example.com/artist/xyz. I was hoping it was as
I'm profiling some old java code and it appears that my caching of values
As part of a profiling tool, I have a custom ADO.NET stack that acts
We have a legacy 3rd party program that is failing with the error Class
I have a class that looks like this: typedef std::list<char*> PtrList; class Foo {
Instead of writing: @holder = split /\./,hello.world; print @holder[0]; is it possible to just

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.