int a;
printf("%d\n", a);
I wonder if %d is a cast?
int a; printf(%d\n, a); I wonder if %d is a cast?
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In any case it won’t be a cast but a reinterpretation (like getting the address, casting to a pointer of a different type and then getting the contents as a new type).
Example:
won’t print integer
1, but the integer value of the representation of1.5in IEEE 754. If you want to cast, you must explicitly put(int)in front of the value.