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Asked: 2026-05-25T20:02:18+00:00

int bar[10]; /* bar is array 10 of int, which means bar is a

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int bar[10]; /* bar is array 10 of int, which means bar is a pointer to array 10 of int */

int (*bar)[10]; /* bar is a pointer to array 10 of int */

According to me they both are same, am I wrong? Please tell me.

Edit: int *bar[10] is completely different.

Thanks
Raja

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1 Answer

  1. Editorial Team

    They are completely different. The first one is an array. The second one is a pointer to an array.

    The comment you have after the first bar declaration is absolutely incorrect. The first bar is an array of 10 ints. Period. It is not a pointer (i.e. your “which means” part makes no sense at all).

    It can be expressed this way:

    typedef int T[10];

    Your first bar has type T, while you r second bar has type T *. You understand the difference between T and T *, do you?

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