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Editorial Team
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Asked: 2026-05-15T22:05:01+00:00

int foo(int){ … } Any ideas?

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int foo(int){      
     ...  
}

Any ideas?

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1 Answer

  1. Editorial Team

    One case where you define a function but do not name the parameter is given in Scott Meyers’s “Effective C++, 3rd edition”, Item 47:

    template<typename IterT, typename DistT>        
void doAdvance(IterT& iter, DistT d,            
               std::random_access_iterator_tag) 
{
  iter += d;
}

    is used in:

    template<typename IterT, typename DistT>
void advance(IterT& iter, DistT d)
{
  doAdvance( iter, d, 
             typename std::iterator_traits<IterT>::iterator_category() );
}

    Essentially, the third parameter in doAdvance is a type unaccompanied by a variable name, i.e. it is an unnamed parameter. Having an unnamed parameter isn’t a problem, since that argument is only used during the resolution of which overloaded function to use. I discuss these topics in this related SO question.

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