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Home/ Questions/Q 7508553
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T22:41:34+00:00 2026-05-29T22:41:34+00:00

int i; i=0; for (i=0;i>2;i++) { repeat((3),|,var); printf(\n); } For some reason it gets

  • 0
int i;
i=0;
for (i=0;i>2;i++)
    {
     repeat((3),"|",var);
     printf("\n");          
    }

For some reason it gets to the “for” and it skips it. I tried to put the int i outside of the for and even initialized it outside of the for and in debug it is zero. all I need it to do is loop through this code twice.

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  1. Editorial Team
    Editorial Team
    2026-05-29T22:41:35+00:00Added an answer on May 29, 2026 at 10:41 pm

    Change:

    for (i=0;i>2;i++)
    

    to:

    for (i=0;i<2;i++)
    

    You’re testing if it’s > 2 which will fail so it never enters the loop.

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