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Home/ Questions/Q 6875241
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:17:50+00:00 2026-05-27T04:17:50+00:00

int main () { try { try { throw 5; } catch (int n)

  • 0
int main ()
{
    try
    {
        try
        {
            throw 5;
        }
        catch (int n)
        {
            throw;
        }
    }
    catch (...)
    {
        cout << "Exception occurred";
    }
}

This prints out “Exception occured” but

int main ()
{
    try
    {
        try
        {
            throw;
        }
        catch (...)
        {
            throw;
        }
    }
    catch (...)
    {
        cout << "Exception occurred";
    }
}

This just errors. It seems like I’m doing the try-catch’s exactly the same! The only difference is that in the first case I’m throwing an int, then a general exception, but in the second case, I’m throwing a general exception both times. Is the program confused as to which catch to go to?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:17:51+00:00Added an answer on May 27, 2026 at 4:17 am

    There’s no such thing as “general exception” and you throw no such thing.

    In the first example, you throw an int, then you re-throw the exception that you are handling. That’s the meaning of throw without an argument.

    In the second example you start with an attempt to re-throw an exception that you are handling. As you are not handling an exception at that time, you get an error.

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