Question

int main(int argc, char** argv) {
    char *test[5][20];
    char *input[20];
    int i;
    for(i=0;i<5;i++){

    printf("enter> ");
    fflush ( stdout );
    fgets(input,20,stdin);
         *test[i] = *input;
    }

    for(i=0;i<5;i++)
       printf("%d | %s\n",i,test[i]);
    return 0;
}

Output:

enter> pwd

enter> pathd

enter> ls

enter> echo $path

enter> pwd 0 | pwd

1 | path▒] a▒▒a▒▒#a▒▒ 2 | ls

3 | echo▒▒( 4 | pwd

Press [Enter] to close the terminal
…

I also need to be able to read in input that has spaces. Thanks!

Answer 1

Use memcpy(). And you need to strip trailing newlines. Here:

#include <stdio.h>
#include <string.h>

void chopnl(char *s) {              //strip '\n'
    s[strcspn(s, "\n")] = '\0';
}

int main() {
    char test[5][20];
    char input[20];
    int i;
    for(i=0;i<5;i++){
        printf("enter> ");
        fflush ( stdout );
        fgets(input, 20, stdin);
        chopnl(input);
        memcpy(test[i], input, strlen(input)+1);//test[i] = input;
    }
    for(i=0;i<5;i++)
       printf("%d | %s\n",i,test[i]);
    return 0;
}