Question

int main(int argc, char **argv){

    // If the user does not have the right amount of arguments exit the program and display message
    if(!(argc >= 2)){
        printf("Usage: %s -l -c -w -L <filenames>");
        exit(-1);
    }

    size_t iscFlag = 0;
    size_t islFlag = 0;
    size_t iswFlag = 0;
    size_t isLFlag = 0;
    FILE *src; 
    puts("Work work");  
    // For loop that checks for all the flags
    int i;
    for(i = 1; i < 5; i++){
        if(strcmp(argv[i], "-c") == 0){
            iscFlag = 1;            
        }else if(strcmp(argv[i], "-l") == 0){
            islFlag = 1;
        }else if(strcmp(argv[i], "-w") == 0){
            iswFlag = 1;
        }else if(strcmp(argv[i], "-L") == 0){
            isLFlag = 1;
        }
    }

I’m trying to make a simple for loop that checks for flags to recreate a wc command in a UNIX type terminal. Anyone know what’s up with the for loop? I get a segmentation fault on it. There is more code but I’m just posting a part of it.

Thanks in advance.

Answer 1

With

for(i = 1; i < 5; i++){
    if(strcmp(argv[i], "-c") == 0){

you should ensure that argc >= 5, or the strcmp will receive a NULL pointer when i == argc.