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Home/ Questions/Q 8626585
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T08:04:06+00:00 2026-06-12T08:04:06+00:00

int main(int argc, char *argv[]) { printf(Temp is); msgrcv(externalQid, &incomingMsg, sizeof(incomingMsg)-sizeof(long), 0, 0); }

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int main(int argc, char *argv[])
{
printf("Temp is");

msgrcv(externalQid, &incomingMsg, sizeof(incomingMsg)-sizeof(long), 0, 0);
}   

printf never actually prints in this case…it does however get printed if I don’t have the msgrv call.. It is making it very hard to debug my program. Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-12T08:04:08+00:00Added an answer on June 12, 2026 at 8:04 am

    Try putting a newline character at the end of your printf. I’m not intimately familiar with the ‘why’, but it solved a similar problem I had a while ago.

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