Question

int main(void) {
  int x = 0;
  int* p = &x;
  char* q = p;
  while (*p == *q) { //What happens here?
     x = x + 1;
  }
  printf(“%d\n”, x);
}

Well I have this simple program here. I am confused on how this works. I would be obliged if you can help me.

I have a test and would like to learn how this works. Thank you in advance.

Q Pointer Question

|—————————-|

               0x00<————-Q points here?
|—————————-|

               0x00
|—————————-|

               0x00
|—————————-|

               0x00<————-Q points here?
|—————————-|

So after x = x+1. Is it?

|—————————-|

               0x00<————-0x01 here?
|—————————-|

               0x00
|—————————-|

               0x00
|—————————-|

               0x00<————-0x01 here?
|—————————-|

Answer 1

It depends on endianness, but it’s essentially:

while (x == ((char) x)) {
    ++x;
}

The loop will terminate once ((int) x) != ((int) lowest byte of x)