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Home/ Questions/Q 7988843
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T12:34:33+00:00 2026-06-04T12:34:33+00:00

int n ; n= (int)( javax.swing.JOptionPane.showInputDialog(null,enter a 3 digit no.)); Why does the above

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int n ;
n= (int)( javax.swing.JOptionPane.showInputDialog(null,"enter a 3 digit no."));

Why does the above gives error[required int, found string] and the below one works fine ?

int n ;
n= Integer.parseInt( javax.swing.JOptionPane.showInputDialog(null,"enter a 3 digit no."));
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  1. Editorial Team
    Editorial Team
    2026-06-04T12:34:35+00:00Added an answer on June 4, 2026 at 12:34 pm

    Integer.parseInt doesn’t use casting but rather a simple algorithm to interpret the digits in the string as a number. Casting is done by the JVM directly on the primitive value or the compiler on the object reference. It can turn 4.5 into 4 (type conversion as it changes the underlying value) and ArrayList into List (reference casting as it doesn’t modify the instance), but it cannot parse or format numbers natively.

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