Question

int number = 5;

Type dynamicType = number.GetType();    // dynamic type is "int"

dynamicType x = (number as dynamicType);

Answer 1

How would you expect the compiler to treat the variable x later in the code? It wouldn’t know anything about it… so it couldn’t resolve any method calls etc.

Basically what you’re after is dynamic typing which is supported in C# 4 with the “dynamic” pseudo-type:

int number = 5;
dynamic d = number;
// Calls to d are resolved at execution time, so this compiles:
d.ThisWillThrowAtExecutionTime();