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Editorial Team
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Asked: 2026-05-14T01:40:06+00:00

Integer i = 127; Integer j = 127; System.out.println(i == j); System.out.println(i.equals(j)); Integer i1

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Integer i = 127;
Integer j = 127;
System.out.println(i == j);
System.out.println(i.equals(j));

Integer i1 = 128;
Integer j1 = 128;
System.out.println(i1 == j1);
System.out.println(i1.equals(j1));

I don’t understand why its not print “true, true, true, true”. please give answer?

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1 Answer

  1. Editorial Team

    When you use ==, you’re comparing the object instances for equality.

    The reason that the first two instances are equal is that you created the Integers by using autoboxing (rather than calling new Integer(127)), and the Java Language Specification §5.1.7 requires that Integers between -128 and 127 are cached.

    Implementations can cache more values than that but are not required to; apparently the JVM you are using does not cache 128. This is the case for Sun Java 6.

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