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Home/ Questions/Q 8688845
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T23:28:50+00:00 2026-06-12T23:28:50+00:00

Intent: call an external application with specified arguments, and exit script. The following script

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Intent: call an external application with specified arguments, and exit script.

The following script does not work as it should:

 #!/usr/bin/node
 var cp = require('child_process');
 var MANFILE='ALengthyNodeManual.pdf';
 cp.spawn('gnome-open', ['\''+MANFILE+'\''], {detached: true});

Things tried: exec – does not detach. Many thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-06-12T23:28:52+00:00Added an answer on June 12, 2026 at 11:28 pm

    From node.js documentation:

    By default, the parent will wait for the detached child to exit. To prevent the parent from waiting for a given child, use the child.unref() method, and the parent’s event loop will not include the child in its reference count.

    When using the detached option to start a long-running process, the process will not stay running in the background unless it is provided with a stdio configuration that is not connected to the parent. If the parent’s stdio is inherited, the child will remain attached to the controlling terminal.

    You need to modify your code something like this:

    #!/usr/bin/node
    var fs = require('fs');
    var out = fs.openSync('./out.log', 'a');
    var err = fs.openSync('./out.log', 'a');
    
    var cp = require('child_process');
    var MANFILE='ALengthyNodeManual.pdf';
    var child = cp.spawn('gnome-open', [MANFILE], { detached: true, stdio: [ 'ignore', out, err ] });
    child.unref();
    
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