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Home/ Questions/Q 1116173
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T03:15:47+00:00 2026-05-17T03:15:47+00:00

// InternalTemplate.cpp : Defines the entry point for the console application. // #include stdafx.h

  • 0
// InternalTemplate.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"

template<class T>
struct LeftSide
{
 static void insert(T*& newLink, T*& parent)
 {
  parent->getLeft() = newLink;
  newLink->parent = newLink;
 }
};

template<class T>
struct Link
{
 T* parent_;
 T* left_;
 T* right_;
 T*& getParent()const
 {
  return parent_;
 }
 template<class Side>
 void plugIn(Link<T>*& newLink);


};

template<class T>
template<class Side>
void Link<T>::plugIn(Link<T>*& newLink)//<<-----why can't I type  
//void Link<T>::plugIn<Side>(Link<T>*& newLink)<---<Side> next to plugIn


{
 Side::insert(newLink,this);
}

int _tmain(int argc, _TCHAR* argv[])
{
 return 0;
}

I find it strange that I have to specify parameter for a class but cannot specify parameter for a function. Is there any reason why?

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  1. Editorial Team
    Editorial Team
    2026-05-17T03:15:48+00:00Added an answer on May 17, 2026 at 3:15 am

    $14/2 –

    A template-declaration can appear only as a namespace scope or class scope declaration. In a function template declaration, the last component of the declarator-id shall be a template-name or operator-functionid (i.e., not a template-id). [ Note: in a class template declaration, if the class name is a simple-template-id, the declaration declares a class template partial specialization (14.5.5). —end note ]”

    The standard forbids such a syntax explicitly. Refer this for more idea about template id / template name

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