Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7796567
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T23:24:40+00:00 2026-06-01T23:24:40+00:00

Interview question: Calculate x ^ y in O(log n) There are different answers like

  • 0

Interview question:

Calculate x ^ y in O(log n)

There are different answers like “Use the Indian Power algorithm” or

double power(double x, int y) 
{
    if(y == 0) return 1;

    double d = power(x, y/2);

    if(y%2 == 0) return d*d;
    else return x*d*d;
}
  1. is it a correct answer?

  2. is there any better way of writing a code for this question?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-01T23:24:43+00:00Added an answer on June 1, 2026 at 11:24 pm

    This is called Exponentiation by Squaring. As far as implementation goes, it is a matter of taste. Your recursive implementation is good, but non-recursive implementations (from the link above) may look a little cleaner to people who do not like recursion or erroneously believe that it is somehow “wasteful” or “slow”.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

This is an interview question asked a month ago.... Do session use cookies? If
This is an interview question, and should concern about efficiency. How to calculate occurrences
An interview question: write SQL Server query to return 30th to 40th record of
This is an interview question. There are some random numbers given (let's say in
I recently faced an interview question related to LINQ. What is the use of
I was asked an interview question where I needed to use it but I
I came across an interview question: Given life times of different elephants. Find the
I got this question today in an interview: write a function to calculate the
I've encountered this interview question and would like some help in trying to understand
I found this interview question, and I couldn't come up with an algorithm better

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.