Question

Is \d++ a valid regular expression in programming languages that don’t support possessive quantifier?Is it equivalent to (\d+)+?

When testing it in Python,an error sre_constants.error: multiple repeat will be raised.In C#,it will throw a runtime exception:System.ArgumentException: parsing "\d++" - Nested quantifier +.As well as boost::xpressive.
But \d++...+ is considered valid in boost::regex.

wchar_t* s = L"abc123" ;
wregex e(L"\\d+++", boost::regex::normal) ;
wcmatch m ;

if(regex_search(s, m, e)){
    wcout <<  m[0] << endl ;
}

The output is 123.

Answer 1

The above code throws an instance of boost::bad_expression with “Invalid preceding regular expression” for me.
Its a redhat linux system compiled with gcc 3.4.6 and boost 1_32.