Question

Is it a correct way to compare Intents? I never get in to the if/else regardless the incoming Intent is android.Intent.action.VIEW (the value intent.getAction() returns):

    private void handleIntent(Intent intent) {
Log.d(TAG, intent.getAction()); // -> android.Intent.action.VIEW
            if (Intent.ACTION_VIEW.equals(intent.getAction())) {
                ShowToast.showToast(this, "Something..."); // Never get here
            } else if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
                String query = intent.getStringExtra(SearchManager.QUERY);
                showResults(query);
            }
        }

Update: Why does the intent.getAction() returns android.Intent.action.VIEW (capital ‘i’) while it should return android.intent.action.VIEW as in specification?

Answer 1

I found where the capital ‘i’ came from. As long as I’m using the SearchView I specify what Intent to be used when new Activity would start by myself, so I just made a mistake here:

<searchable xmlns:android="http://schemas.android.com/apk/res/android"
            android:label="@string/appname"
            android:hint="@string/search_hint"
            android:searchSuggestAuthority="my.package.dataproviders.TicketSuggestionProvider"
            android:searchSuggestIntentData="content://my.package.dataproviders.TicketSuggestionProvider/titleslist"
            android:searchSuggestIntentAction="android.Intent.action.VIEW" // HERE IT IS
            android:searchSuggestSelection=" ?">
</searchable>