Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 1034033
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T14:19:34+00:00 2026-05-16T14:19:34+00:00

Is it O(n log n) or O(log n)?

  • 0

Is it O(n log n) or O(log n)?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T14:19:35+00:00Added an answer on May 16, 2026 at 2:19 pm

    I’m going to say it’s not O(log n) because binary searches don’t work well on linked lists – you don’t have efficient random access.

    If you really tried to do binary search, it would take O(log n) steps, but in each step, you need an O(n) traversal to access the desired element. So you could say it’s O(nlog(n)).

    You should just do a O(n) linear search instead.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

LOG: Runtime Installer begin with version 3.3.0.3650 on Mac OS 10.7.4 x86 Commandline is:
log.original_fields is always null. why? var updateChangeLog = function(log, currentRecord) { var records, record;
LogIn class where my database is used: package edu.flying.panda.taskmanager; import android.util.Log; import android.view.View; import
log.debug(Id: + domain.id) being domain.id a long value, I get the exception: Exception Message:
Log.d(TAG, Build.VERSION_CODES.ICE_CREAM_SANDWICH: + Build.VERSION_CODES.ICE_CREAM_SANDWICH); I write code like this, I used the sdk4.0 to
logpath = LoggerUtils.getProperties().getProperty(log.path); System.out.println(logpath: + logpath); The above code returns: logpath: C:UsersMauriceDesktopLogs In the
log4perl has a threshold option in the configuration file that will log all calls
Log.d isn't sufficient for pushing a bunch of image data. Is there an easy
Log Parser is great tool for parsing log files. I can parse not just
(log n)^k = O(n)? For k greater or equal to 1. My professor presented

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.