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Home/ Questions/Q 6935951
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:10:13+00:00 2026-05-27T12:10:13+00:00

Is it possible in PHP to require an arbitrary file without leaking any variables

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Is it possible in PHP to require an arbitrary file without leaking any variables from the current scope into the required file’s variable namespace or polluting the global variable scope?

I’m wanting to do lightweight templating with PHP files and was wondering for purity sake if it was possible to load a template file without any variables in it’s scope but the intended ones.

I have setup a test that I would like a solution to pass. It should beable to require RequiredFile.php and have it return Success, no leaking variables..

RequiredFile.php:

<?php

print array() === get_defined_vars()
    ? "Success, no leaking variables."
    : "Failed, leaked variables: ".implode(", ",array_keys(get_defined_vars()));

?>

The closest I’ve gotten was using a closure, but it still returns Failed, leaked variables: _file.

$scope = function( $_file, array $scope_variables ) {
    extract( $scope_variables ); unset( $scope_variables );
    //No way to prevent $_file from leaking since it's used in the require call
    require( $_file );
};
$scope( "RequiredFile.php", array() );

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:10:14+00:00Added an answer on May 27, 2026 at 12:10 pm

    Look at this:

    $scope = function() {
        // It's very simple :)
        extract(func_get_arg(1));
        require func_get_arg(0);
    };
    $scope("RequiredFile.php", []);
    
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