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Home/ Questions/Q 5933605
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T14:59:47+00:00 2026-05-22T14:59:47+00:00

Is it possible to access the ‘owner’ class inside a descriptor during the __init__

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Is it possible to access the ‘owner’ class inside a descriptor during the __init__ function of that descriptor, without passing it in manually as in this example?

class FooDescriptor(object):
    def __init__(self, owner):
        #do things to owner here
        setattr(owner, 'bar_attribute', 'bar_value')


class BarClass(object):
    foo_attribute = FooDescriptor(owner=BarClass)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T14:59:48+00:00Added an answer on May 22, 2026 at 2:59 pm

    One way to do something like that is with a metaclass. Just make sure it’s really what you want, and don’t just copy blindly if you don’t understand how it works.

    class Descriptor(object):
        pass
    
    class Meta(type):
        def __new__(cls, name, bases, attrs):
            obj = type.__new__(cls, name, bases, attrs)
            # obj is now a type instance
    
            # this loop looks for Descriptor subclasses
            # and instantiates them, passing the type as the first argument
            for name, attr in attrs.iteritems():
                if isinstance(attr, type) and issubclass(attr, Descriptor):
                    setattr(obj, name, attr(obj))
    
            return obj
    
    class FooDescriptor(Descriptor):
        def __init__(self, owner):
            owner.foo = 42
    
    class BarClass(object):
        __metaclass__ = Meta
        foo_attribute = FooDescriptor # will be instantiated by the metaclass
    
    print BarClass.foo
    

    If you need to pass additional arguments, you could use e.g. a tuple of (class, args) in the place of the class, or make FooDescriptor a decorator that would return a class that takes only one argument in the ctor.

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