Question

Is it possible to bypass an if statement when delimiting a list that has both a presence and absence of a ‘,’ delimiter? I would like to delimit each list in this the list of list below when a ‘,’ is present. However, some of the lists don’t have a ‘,’.

oldcode = [['a, b'], ['a'], ['a,b,c']]

oldcode_split = []

for code in oldcode:
    oc = code.split(',')
    oldcode_split.append(oc)
print oldcode_split

I would like this result:

oldcode_split = [['a','b'], ['a'], ['a','b','c']]

Thanks!

Answer 1

yes it is possible, use a simple list comprehension:

In [63]: lis = [['a, b'], ['a'], ['a,b,c']]

In [64]: [x[0].split(',') for x in lis]
Out[64]: [['a', ' b'], ['a'], ['a', 'b', 'c']]

using map():

In [66]: map(lambda x:x[0].split(','),lis)
Out[66]: [['a', ' b'], ['a'], ['a', 'b', 'c']]