Question

Is it possible to call the base method from a prototype method in JavaScript if it’s been overridden?

MyClass = function(name){     this.name = name;     this.do = function() {         //do somthing      } };  MyClass.prototype.do = function() {       if (this.name === 'something') {         //do something new     } else {         //CALL BASE METHOD     } }; 

Answer 1

I did not understand what exactly you’re trying to do, but normally implementing object-specific behaviour is done along these lines:

function MyClass(name) {     this.name = name; }  MyClass.prototype.doStuff = function() {     // generic behaviour }  var myObj = new MyClass('foo');  var myObjSpecial = new MyClass('bar'); myObjSpecial.doStuff = function() {     // do specialised stuff     // how to call the generic implementation:     MyClass.prototype.doStuff.call(this /*, args...*/); }