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Home/ Questions/Q 9015565
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T03:46:44+00:00 2026-06-16T03:46:44+00:00

Is it possible to call the current classes methods in a class inheritance? Lets

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Is it possible to call the current classes methods in a class inheritance?

Lets say we have a class A and a Class B which inherits from A. Now both have an “initialize” method, meaning it gets overriden in B. Now i can not use “base.initialize” to call A’s “initialize” from there. Instead im trying to call it from the lower classes constructor (so A’s constructor), which gets called for all inherited classes.

So now i want to call A’s “initialize” on A’s constructor. But when i try that, the overriding constructor of B gets called.

So is there something to tell VS (or c#) that i’m explicitly calling the methods of the class im currently in (this.method() didn’t work)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T03:46:46+00:00Added an answer on June 16, 2026 at 3:46 am

    If you mark a method Initialize as virtual, that means that a derived class is free to override that method, potentially not calling base.Initialize in the process. If it is not okay if that scenario occurs, then don’t mark the method as virtual.

    In your case, it sounds like you just need two private Initialize methods in each class:

    public class A
    {
        public A()
        {
            Initialize();
        }
    
        private void Initialize()
        {
        }
    }
    
    public class B : A
    {
        public B()
        {
            Initialize();
        }
    
        private void Initialize()
        {
        }
    }
    

    Alternatively, you might want to have a look at the Template Method design pattern. You could design your classes like this:

    public class A
    {
        public A()
        {
            Initialize();
        }
    
        private void Initialize()
        {
            // Initialize the base class A.
    
            // Then call DerivedInitialize. If this is actually a derived object,
            // DerivedInitialize will initialize the derived instance. Otherwise,
            // it won't do anything.
            DerivedInitialize();
        }
    
        protected virtual void DerivedInitialize()
        {
        }
    }
    
    public class B : A
    {
        public B()
        {
            Initialize();
        }
    
        protected override void DerivedInitialize()
        {
            // Initialize B-specific stuff...
        }
    }
    
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