Question

Is it possible to change the address of my current struct using the — or ++ operator, i.e.:

mystruct* test = existing_mystruct;
test++ // instead of using: test = test->next_p;

I was trying to use this, but it seems to be const and gives me an Error: assignment to this (anachronism):

struct mystruct {
    mystruct* next_p;
    mystruct* prev_p;

    void operatorplusplus  () { this = next_p; }
    void operatorminusminus() { this = prev_p; }
};

Answer 1

Objects have a constant address in memory while they exist.
You may copy them to a new address, however.

What you try to do is advance in a linked list. And it may be done with those operators if you overload them. But you will need to define that in a special handle class to wrap over the list nodes.

EDIT

The code for what I describe will look somewhat like this:

class mylist
{
  struct mynode
  {
    //data
    mynode* next;
    mynode* prev;
  } *curr;

public:
 mylist& operator++() {curr = curr->next; return *this;}
};

Naturally you’d wanna do boundry checks and such, but that’s the general idea.