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Home/ Questions/Q 6245451
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T12:30:28+00:00 2026-05-24T12:30:28+00:00

is it possible to count fields where something? I have following query: SELECT *

  • 0

is it possible to count fields where something?

I have following query:

SELECT * FROM 
(SELECT messages.id as id,
       messages.user_id,
       messages.category_id,
       messages.parent_id,
       messages.message,
       messages.create_date,
       messages.update_date,
       messages.status,
       users.name as username,
       users.id as userid,
       users.email as useremail,
       users.phone as userphone,
       users.active as useractive,
       users.role as userroel,
       users.date as register_date
FROM `afo_messages` as messages 
INNER JOIN `key_users` as users ON messages.user_id = users.id
WHERE messages.category_id=5 AND messages.parent_id=0
ORDER BY messages.id DESC LIMIT 30) ilv 
ORDER BY id ASC

(Here is example of output: http://lab.mirgorod.us/res.pdf)

Is it possible to add one more column to this query: Count of messages that are childs (parent_id = id of parent message)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T12:30:29+00:00Added an answer on May 24, 2026 at 12:30 pm

    You can do it easily with sub query:

    SELECT * FROM 
    (SELECT messages.id as id,
           messages.user_id,
           messages.category_id,
           messages.parent_id,
           messages.message,
           messages.create_date,
           messages.update_date,
           messages.status,
           users.name as username,
           users.id as userid,
           users.email as useremail,
           users.phone as userphone,
           users.active as useractive,
           users.role as userroel,
           users.date as register_date,
           (SELECT COUNT(*) FROM afo_messages WHERE parent_id=messages.id) AS `sub messages`
    FROM `afo_messages` as messages 
    INNER JOIN `key_users` as users ON messages.user_id = users.id
    WHERE messages.category_id=5 AND messages.parent_id=0
    ORDER BY messages.id DESC LIMIT 30) ilv 
    ORDER BY id ASC
    
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