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Home/ Questions/Q 9184303
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T19:00:51+00:00 2026-06-17T19:00:51+00:00

Is it possible to create a dictionary comprehension in Python (for the keys)? Without

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Is it possible to create a dictionary comprehension in Python (for the keys)?

Without list comprehensions, you can use something like this:

l = []
for n in range(1, 11):
    l.append(n)

We can shorten this to a list comprehension: l = [n for n in range(1, 11)].

However, say I want to set a dictionary’s keys to the same value.
I can do:

d = {}
for n in range(1, 11):
     d[n] = True # same value for each

I’ve tried this:

d = {}
d[i for i in range(1, 11)] = True

However, I get a SyntaxError on the for.

In addition (I don’t need this part, but just wondering), can you set a dictionary’s keys to a bunch of different values, like this:

d = {}
for n in range(1, 11):
    d[n] = n

Is this possible with a dictionary comprehension?

d = {}
d[i for i in range(1, 11)] = [x for x in range(1, 11)]

This also raises a SyntaxError on the for.

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  1. Editorial Team
    Editorial Team
    2026-06-17T19:00:53+00:00Added an answer on June 17, 2026 at 7:00 pm

    There are dictionary comprehensions in Python 2.7+, but they don’t work quite the way you’re trying. Like a list comprehension, they create a new dictionary; you can’t use them to add keys to an existing dictionary. Also, you have to specify the keys and values, although of course you can specify a dummy value if you like.

    >>> d = {n: n**2 for n in range(5)}
    >>> print d
    {0: 0, 1: 1, 2: 4, 3: 9, 4: 16}
    

    If you want to set them all to True:

    >>> d = {n: True for n in range(5)}
    >>> print d
    {0: True, 1: True, 2: True, 3: True, 4: True}
    

    What you seem to be asking for is a way to set multiple keys at once on an existing dictionary. There’s no direct shortcut for that. You can either loop like you already showed, or you could use a dictionary comprehension to create a new dict with the new values, and then do oldDict.update(newDict) to merge the new values into the old dict.

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