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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:59:42+00:00 2026-05-14T20:59:42+00:00

Is it possible to do the same using Lambda for (int i = 0;

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Is it possible to do the same using Lambda

for (int i = 0; i < objEntityCode.Count; i++)
{
    options.Attributes[i] = new EntityCodeKey();
    options.Attributes[i].EntityCode = objEntityCode[i].EntityCodes;
    options.Attributes[i].OrganizationCode = Constants.ORGANIZATION_CODE;
}

I mean to say to rewrite the statement using lambda. I tried with

Enumerable.Range(0,objEntityCode.Count-1).Foreach(i=> { 
    options.Attributes[i] = new EntityCodeKey(); 
    options.Attributes[i].EntityCode = objEntityCode[i].EntityCodes; 
    options.Attributes[i].OrganizationCode = Constants.ORGANIZATION_CODE; }
);

but not working
I am using C#3.0

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:59:43+00:00Added an answer on May 14, 2026 at 8:59 pm

    Well you can make it simpler with object initializers, to start with:

    for (int i = 0; i < objEntityCode.Count; i++)
    {
        options.Attributes[i] = new EntityCodeKey
        {
            EntityCode = objEntityCode[i].EntityCodes,
            OrganizationCode = Constants.ORGANIZATION_CODE
        };
    }
    

    I would probably leave it at that though… there’s currently no ForEach extension method on IEnumerable<T> – and for good reasons, although I know it’s not a universally held opinion 😉

    In this case, you’d still need to know i in order to set options.Attributes[i] – unless you could set the whole of options.Attributes in one go, of course… without knowing about the types involved, it’s pretty hard to advise further.

    If options.Attributes is a writable property (e.g. an array), you could use:

    options.Attributes = objEntityCode.Select(code => new EntityCodeKey
        {
            EntityCode = code.EntityCodes,
            OrganizationCode = Constants.ORGANIZATION_CODE
        }).ToArray();
    

    If options.Attributes is actually just a property which returns a type with an indexer, that won’t work.

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