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Home/ Questions/Q 8655905
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T15:09:07+00:00 2026-06-12T15:09:07+00:00

is it possible to do things like this: def f(): d={} d[1]=’qwe’ d[2]=’rty’ return

  • 0

is it possible to do things like this:

def f():
  d={}
  d[1]='qwe'
  d[2]='rty'
  return d

a,b=f()[1:2]

not a,b=f()[1],f()[2]
and not

t=f()
a,b=t[1],t[2]

I wont avoid extra lines and call function only once.

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  1. Editorial Team
    Editorial Team
    2026-06-12T15:09:07+00:00Added an answer on June 12, 2026 at 3:09 pm

    No; dictionary indexing doesn’t support slicing, since it usually doesn’t make any sense in dictionary keys.

    You can roll it yourself, though, with something like

    a, b = map(f().get, [1, 2])
    

    or (thanks @DSM)

    a, b = operator.itemgetter(1, 2)(f())
    

    These are slightly different in that if the result of f() is missing 1 or 2 as keys, the first will default to assigning None and the second will raise KeyError. map(f().__getitem__, ...) should be equivalent to itemgetter, though probably slightly slower.

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