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Home/ Questions/Q 7815973
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T05:41:56+00:00 2026-06-02T05:41:56+00:00

Is it possible to do this? Lets say I have a table : data

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Is it possible to do this?

Lets say I have a table : data

$id_1 = "checking";
$id_2 = "box";
$id_users = 1;

id    id_1        id_2         id_users
1     checking    box             1
2     checking    circle          1
3     box         checking        1
4     box         checking        1

$sql = $db->prepare("SELECT COUNT(*) FROM data WHERE ((id_1 = ? AND id_2= ?) OR (id_1 = ? AND id_2 = ?)) AND id_users = ?");
$sql -> execute(array($id_1, $id_2, $id_2, $id_1, $id_users));
echo count($sql);

With this, I’m getting an output of 1 only. Technically I should be getting an output of 3, correct? Because there are 3 possibilities with checking and box.

The SQL is supposed to check either table for the two combinations of checking and box.

Can someone tell me what I’m doing wrong here?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-02T05:41:59+00:00Added an answer on June 2, 2026 at 5:41 am

    What MДΓΓ БДLL said is ok, but you could also use named parameters:

    $sql = $db->prepare("SELECT COUNT(*) FROM data WHERE ((id_1 = :id1 AND id_2= :id2) OR (id_1 = :id2 AND id_2 = :id1)) AND id_users = :idusers");
    $sql -> execute(array(':id1' => $id_1, ':id2' => $id_2, ':idusers' => $id_users));
    

    And you need to fetch result

    $result = $sql->fetch();
    echo $result[0];
    
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