Question

Is it possible to draw any view inside bounded region inside GLSurfaceView or SurfaceView?

At the moment my GLSurfaceView is filled with Bitmap textures.

I want to achieve something like this

   +---------------------------------+
   |                                 |
   |         GLSurfaceView           |
   |                                 |
   |        +-------------+          |
   |        |WhateverView/|          |
   |        | Layout/     |          |
   |        |ViewGroup    |          |
   |        +-------------+          |
   |                                 |
   +---------------------------------+

I’ve tried doing this with FrameLayout to draw the View on the top of the GLSurfaceview, but that is not what I’m trying to achieve.

Thanks.

Answer 1

I had a same issue. I used this tricks below.

Use AbsoluteLayout to overlap GLSurfaceView and other View.

AbsouluteLayout -+-- GLSurfaceView
                 +-- View

Set GLSurfaceView transparent.

mGlSurfaceView.setEGLContextClientVersion(2);
mGlSurfaceView.setEGLConfigChooser(8, 8, 8, 8, 16, 0);
mGlSurfaceView.getHolder().setFormat(PixelFormat.TRANSLUCENT);
mGlSurfaceView.setRenderer(new GLES20TriangleRenderer(this));
mGlSurfaceView.setZOrderOnTop(true);

Add a punching hole. do not render an overlapping region in GLSurfaceView. OnTouchListener that is attached to GLSurfaceView returns false in the overlapping region to propagate events to other views.

PS: Sorry for my poor english.