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Home/ Questions/Q 7996255
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T14:39:54+00:00 2026-06-04T14:39:54+00:00

is it possible to evaluate each individual in the population using the fitness value

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is it possible to evaluate each individual in the population using the fitness value without finding the probability as the following pseudo code

For all members of population
    sum += fitness ( member)
End for 
Loop until new population is full 
      Do this twice 
            Number = Random between 0 and sum
            Currentfitness = 0.0
            For each member in population
               Currentfitness += fitness (member)
               if Number > Currentfitness then select member
            End for 
      End
Create offspring 
End loop

and what the following part of the code do ?

Do this twice

I really confuse how the Roulette Wheel selects pair of parents. can any help ? thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-06-04T14:39:55+00:00Added an answer on June 4, 2026 at 2:39 pm

    The code is meant to select a random element, but with probabilities according to a certain weight.

    Example:

    • We want to select from a two-element array with the following weights: { 1, 9 }
    • The cumulative weight is { 1, 10 }
    • The total weight is 10
    • We choose a random number between 1 and 10
    • We look into the cumulative weight array and find the first index where our random number is
      greater than the element
    • This index is the index of the randomly chosen element

    Intuitively, this example makes sense: 9 out of ten times the random number will fall between 1 and 9 causing the first element to be drawn with probability 0.9 (just as the weights specified).

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