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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:35:40+00:00 2026-05-13T14:35:40+00:00

Is it possible to extract the node name using apache digester? So, if the

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Is it possible to extract the node name using apache digester?

So, if the xml looks like

   <furniture>
     <sofa>
       .....
     </sofa>
     <coffeeTable>
       .....
     </coffeeTable>
   </furniture>

is it possible to extract the node name “sofa”, “coffeeTable”?

I know it is possible using xpath but is it possible using digester?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:35:41+00:00Added an answer on May 13, 2026 at 2:35 pm

    (original answer)

    Create a Digester for pattern "furniture/*" with a simple Rule that takes the second parameter to each call to the begin method and sticks it in a collection of your choice (a list to get all of them, a set to get only all unique names).

    (edit)

    Scratch that, it’s a bit more complicated.

    This works:

    public class App 
    {
        final static Rule printRule = new Rule() {
            public void begin(String namespace, String name,
                    Attributes attributes) throws Exception {
                System.out.println(name);
            }
        }; 
        public static void main( String[] args ) throws IOException, SAXException
        {
            InputStream instr = App.class.getResourceAsStream("/sample.xml");
            Digester dig = new Digester();
            dig.setRules(new RulesBase(){
                public List<Rule> match(String namespaceURI, String pattern) {
                    return Arrays.asList(printRule);
                }
            });
            dig.parse(instr);
        }
    }
    

    This particular sample will print all element names including the root furniture element. I’ll leave it to you to adjust the match() method to your needs.

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