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Home/ Questions/Q 8866319
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T16:45:32+00:00 2026-06-14T16:45:32+00:00

Is it possible to instantiate a template class at runtime for example: Type type

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Is it possible to instantiate a template class at runtime for example:

Type type = Type.GetType("iTry.Workflow.Person");
WorkflowPropertyViewModel<type> propViewModel = new WorkflowPropertyViewModel<type>();

This obviously does not work. Is there some other way to do it?

The Generic class looks like the following:

public class WorkflowPropertyViewModel<T> : IProperty<T>  
{
    public Task<T> ValueAsync
    {
        get;
        set;
    }

    public T Value
    {
        get;
        set;
    }

    public IQueryable<T> PossibleItems
    {
        get;
        set;
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T16:45:32+00:00Added an answer on June 14, 2026 at 4:45 pm

    Yes, you can instantiate a generic class with a type known only at runtime, e.g.:

    public class A { }
    public class U<T> {
        public T X { get; set; }
    }
    
    static void Main(string[] args) {
        Type a = typeof(A);
        Type u = typeof(U<>);
        dynamic uOfA = Activator.CreateInstance(u.MakeGenericType(a));
        uOfA.X = new A();
        Console.WriteLine(uOfA.GetType());
        Console.WriteLine(uOfA.X.GetType());
    }
    

    However, this snippet uses reflection and dynamic typing, both of which may cause a lot of maintenance problems, so you would be better off using them very carefully or finding a simpler solution.

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