Question

Is it possible to somehow retrieve the pin code from WebView in Android while authorising the Twitter?

I’ve got tutorial example, but to login user need to rewrite the pin code from WebView to app. I just want to pass this and get pin code directly from web.

This is very similar to how it goes on iPhone.

Now I using something like this:

public void getTwitter() 
{
      handleEvent.post(new Runnable() 
      {

       @Override
       public void run() 
       {               
            if (oHelper.hasAccessToken()) 
            {

                oHelper.configureOAuth(twitterConnection);
                try 
                {
                     twitterConnection.updateStatus("Hii!!!!");
                } 
                catch (TwitterException e) 
                {
                     Log.d("TWEET", "Error Updating status " + e.getMessage());
                     e.printStackTrace();
                }
            } 
            else 
            {
                 try 
                 {
                      twitterConnection.setOAuthConsumer(CONSUMER_KEY,CONSUMER_SECRET);
                      requestToken = twitterConnection.getOAuthRequestToken("");
                      webViewDialog(requestToken.getAuthorizationURL(), 0);
                 } 
                 catch (TwitterException e) 
                 {
                     e.printStackTrace();
                 }
            }
       }

      });
}

then display the webview inside dialog popup:

private void webViewDialog(final String authorizationURL, final int type) 
{
      LinearLayout container = new LinearLayout(this);
      container.setMinimumWidth(200);
      container.setMinimumHeight(320);
      webView = new WebView(this);

      webView.setMinimumWidth(200);
      webView.setMinimumHeight(380);
      webView.getSettings().setJavaScriptEnabled(true);
      webView.setWebViewClient(new WebViewClient());
      webView.loadUrl(authorizationURL);

      container.addView(webView);
      webDialog = new AlertDialog.Builder(this);
      webDialog.setView(container).setPositiveButton("Ok", new DialogInterface.OnClickListener() 
      {

         @Override
         public void onClick(DialogInterface dialog, int which) 
         {
             dia = dialog;
              if (type == 0) 
              {
                   twitterPinCodeDialog();
              }

         }
      }).show();
}

and in the end prompt user to input pincode:

public void twitterPinCodeDialog() 
{
      LinearLayout pinHolder = new LinearLayout(this);
      pinHolder.setGravity(Gravity.CENTER);
      final EditText editPinCode = new EditText(this);
      editPinCode.setGravity(Gravity.CENTER);
      editPinCode.setHint("Pin Code");
      editPinCode.setWidth(200);
      pinHolder.addView(editPinCode);

      Builder pinBuilder = new AlertDialog.Builder(this);
      pinBuilder.setView(pinHolder).setTitle("Twitter Pin Code Entry")
        .setMessage("Please enter displayed twitter code into the field")
        .setPositiveButton("Ok", new DialogInterface.OnClickListener() 
        {

         @Override
         public void onClick(DialogInterface dialog, int which) 
         {
              if (editPinCode.getText().toString() != null && !editPinCode.getText().toString().equals("")) 
              {
                   try 
                   {
                        accessToken = twitterConnection.getOAuthAccessToken(requestToken,editPinCode.getText().toString());
                        oHelper.storeAccessToken(accessToken);
                        Log.i("Access Token:", accessToken.getToken());
                        Log.i("Access Secret:", accessToken.getTokenSecret());
                        twitterConnection.updateStatus("Tweeted Successfully");
                   } 
                   catch (TwitterException te) 
                   {
                        if (401 == te.getStatusCode()) 
                        {
                            System.out.println("Unable to get the access token.");
                        } 
                        else 
                        {
                            te.printStackTrace();
                        }
                   }
              } 
              else 
              {
               Toast.makeText(context, "Pin code is required",
                 Toast.LENGTH_SHORT).show();
               dialog.dismiss();    
               dia.dismiss();
               twitterPinCodeDialog();
               }
         }

        }).setNegativeButton("Cancel",new DialogInterface.OnClickListener() 
        {

           @Override
           public void onClick(DialogInterface dialog,int which) 
           {
                Toast.makeText(context,"To share your news please complete login next time",Toast.LENGTH_LONG).show();
                dialog.dismiss();
           }
          }).show();
     }

I don’t even remember from where I took this example.
But it would be nice to get rid off last dialog.

Answer 1

Yes it is quite possible – I don’t have my code in front of me, but the process is as follows:

• When you make your twitter authorisation request, you provide it with a callback URL, lets call it callback://myapp.twitter.pin
• Register a URL handler in your manifest for this URL
• When the authorisation is successful, the twitter webpage will redirect the user to your callback URL
• Android will intercept the callback URL and resume your login activity
• You can use your onResume to access the PIN from the uri as I demonstrate in my question here