Question

Is it possible to typedef long types that use templates? For example:

template <typename myfloat_t> class LongClassName {     // ... };  template <typename myfloat_t> typedef std::vector< boost::shared_ptr< LongClassName<myfloat_t> > > LongCollection;  LongCollection<float> m_foo; 

This doesn’t work, but is there a way to achieve a similar effect? I just want to avoid having to type and read a type definition that covers almost the full width of my editor window.

Answer 1

No, that isn’t possible currently. It will be made possible in C++0X AFAIK.

The best I can think of is

template<typename T> struct LongCollection {     typedef std::vector< boost::shared_ptr< LongClassName<T> > > type; };  LongCollection<float>::type m_foo;