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Home/ Questions/Q 8581555
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T21:04:52+00:00 2026-06-11T21:04:52+00:00

Is lazy instantiation about using less code but getting the same result? Surely this

  • 0

Is lazy instantiation about using less code but getting the same result? Surely this is generally a good thing to do (providing making the code to short / efficient doesn’t damage readability/maintainability).

Please refer to this lazy instantiation:

public sealed class Singleton
{
    private Singleton()
    {
    }

    public static Singleton Instance { get { return Nested.instance; } }

    private class Nested
    {
        // Explicit static constructor to tell C# compiler
        // not to mark type as beforefieldinit
        static Nested()
        {
        }

        internal static readonly Singleton instance = new Singleton();
    }
} 

There is no private property of Instance (I know it’s implicit) – is it that which makes it lazy – the fact we don’t have a setter within the public static Singleton Instance property?

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  1. Editorial Team
    Editorial Team
    2026-06-11T21:04:53+00:00Added an answer on June 11, 2026 at 9:04 pm

    Lets say we have a field of a type that is expensive to construct

    class Foo
    {
        public readonly Expensive expensive = new Expensive();
        ...
    }
    

    The problem with this code is that instansiating Foo incurs the performance cost of instansiating Expensive – whether-or-not the Expensive field is ever accessed. The obvious answer is to construct the instance on demand or lazily instansiate the field:

    class Foo
    {
        Expensive _expensive;
        public Expensive
        {
            get
            {
                if (_expensive == null) _expensive = new Expensive();
                return _expensive;
            }
        }
        ...
    }
    

    This is lazy instansiation.

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