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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T08:05:50+00:00 2026-06-17T08:05:50+00:00

is possible to cast hash to array in perl but without using further variable

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is possible to cast hash to array in perl but without using further variable ?
This works as expected but another variable (@arr) is used:

perl -wlae '%hash=(name=>"linus", forename=>"torvalds "); @arr=%hash; print "@arr"'

I have tried those but neither worked (BTW what do they do ?):

perl -wlae '%hash=(name=>"linus", forename=>"torvalds "); print "@hash"'
perl -wlae '%hash=(name=>"linus", forename=>"torvalds "); print "%@hash"'
perl -wlae '%hash=(name=>"linus", forename=>"torvalds "); print "@%hash"'
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  1. Editorial Team
    Editorial Team
    2026-06-17T08:05:51+00:00Added an answer on June 17, 2026 at 8:05 am
    perl -wlae '%hash=(name=>"linus", forename=>"torvalds "); print (%hash);'
    

    Putting an expression in parentheses evaluates it in a list context, just like assigning to a list variable does.

    In the case of print, this casting is unnecessary, since it uses list context for both arrays and hashes. But if you want to do other array-style things with a hash, you can use this, e.g.

    $first = (%hash)[0];
    echo $first;
    
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