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Asked: May 10, 20262026-05-10T20:08:11+00:00 2026-05-10T20:08:11+00:00

Is std::string size() a O(1) operation? The implementation of STL I’m using is the

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Is std::string size() a O(1) operation?

The implementation of STL I’m using is the one built into VC++

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  1. 2026-05-10T20:08:12+00:00Added an answer on May 10, 2026 at 8:08 pm

    If you’re asking if MSVC’s implementation of string::size() has constant complexity, then the answer is yes. But Don Wakefield mentioned Table 65 in 23.1 of the C++ Standard where it says that the complexity of size() should follow what’s said in ‘Note A’. Note A says:

    Those entries marked ‘‘(Note A)’’ should have constant complexity.

    However, that does not mean that those entries shall have constant complexity. Standards use very specific terminology, and ‘should’ means that it is not mandatory.

    ‘Note A’ was added to the standard specifically to appease those who believed that size() should be allowed to have linear complexity so it would not be necessary to keep the size when the containers were modified.

    So you can’t rely on size() having constant complexity, but I’m honestly not sure if there are any implementations that do not have a constant string::size().

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