Question

Is the first opeartion faster than the second one ?

  u+= (u << 3) + (u << 1) //first operation
  u+= u*10  //second operation 

Basically both of them does the same thing that is u= u+(10*u)
But i came to knew that first operation is faster than second .
Does the cpu time when operation + different from * . Is multiplication by 10
actually equivalent to 10 addition operations being performed ?

Answer 1

It depends on the capabilities of the underlying CPU, and of the compiler.

Any decent compiler should optimise u*10 into the appropriate bit-shift operations if it believes they would be faster. It may not be able to do the opposite. So always write u*10 if you mean u*10, unless you know you’re working with a bad compiler.