Question

Is the following code correct to create a database in php?

<?php

    $con=mysql_connect('localhost','admin','admin');
    if(!$con)
    {
        die("could not connect:' .mysql_error());
    }


    $sql = "CREATE DATABASE db1";
    mysql_select_db("db1", $con);
    $sql = "CREATE TABLE year
    (
        ayear varchar(10),
        fyear varchar(10)

    )";
    if(isset($_POST['id'])) 
    { 
        $ayear = $_POST['ayear'];
        $fyear = $_POST['fyear'];
        if($ayear != "" && $fyear != "") 
        {
            $query = "INSERT INTO year VALUES ('$ayear', '$fyear')"; 
            $result = mysql_query($query) or die(mysql_error());
        }
        else 
            echo "one of the field is empty";
     } 
    if (!mysql_query($sql,$con))
    {
         die('Error: ' . mysql_error()); 
    }
    mysql_close($con); 

?> 

After executing the code, if i check in MySql for the created database, the database was not created. What is the problem with the code? how can i improvise it? Can’t i use create database command inside the

Answer 1

You just have written query to create database didn’t execute it.replace below code with your code

$sql = "CREATE DATABASE db1";
mysql_query($sql, $con);
mysql_select_db("db1", $con);